Make purpose clear of backgroundColor and foregroundColor functions

The functions just start the colors, they do not end them. It seems
too much to have a function that terminates a color.
This commit is contained in:
Dominik Ritter 2018-08-07 21:21:15 +02:00
commit ebbdb3c1c0
2 changed files with 8 additions and 16 deletions

View file

@ -127,8 +127,8 @@ left_prompt_segment() {
[[ -n $FG_COLOR_MODIFIER ]] && 4="$FG_COLOR_MODIFIER"
local bg fg
[[ -n "$3" ]] && bg="$(backgroundColor $3)" || bg="$(backgroundColor)"
[[ -n "$4" ]] && fg="$(foregroundColor $4)" || fg="$(foregroundColor)"
[[ -n "$3" ]] && bg="$(backgroundColor $3)" || bg="%k"
[[ -n "$4" ]] && fg="$(foregroundColor $4)" || fg="%f"
if [[ $CURRENT_BG != 'NONE' ]] && ! isSameColor "$3" "$CURRENT_BG"; then
echo -n "$bg%F{$CURRENT_BG}"
@ -220,8 +220,8 @@ right_prompt_segment() {
[[ -n $FG_COLOR_MODIFIER ]] && 4="$FG_COLOR_MODIFIER"
local bg fg
[[ -n "$3" ]] && bg="$(backgroundColor $3)" || bg="$(backgroundColor)"
[[ -n "$4" ]] && fg="$(foregroundColor $4)" || fg="$(foregroundColor)"
[[ -n "$3" ]] && bg="$(backgroundColor $3)" || bg="%k"
[[ -n "$4" ]] && fg="$(foregroundColor $4)" || fg="%f"
# If CURRENT_RIGHT_BG is "NONE", we are the first right segment.